WebAssume that there are 'm' terms in an AP (Arithmetic Progression) in total whose first term is 'a' and the common difference is 'd'. Then the formula for the n th term from the last of AP … WebMar 16, 2024 · Answer: d = -2 Step-by-step explanation: Because the sum of first n terms of any AP is in the form (d/2)n² + (a - d/2)n, where d is the common difference and a is the first term. So that the coefficient of n² is half of the common difference. Here in S_n = 4n - n², the coefficient of n² is -1, so that half of common difference is -1.
The sum of first n terms of an ap is 4 n2+2 n find the value of this ap
WebFeb 1, 2024 · The sum of the first n terms of an AP is given by Sn, = 3n^2 - 4n. Determine the AP and the 12th term. ← Prev Question Next Question → +3 votes 79.8k views asked Feb 1, 2024 in Mathematics by Kundan kumar (51.5k points) The sum of the first n terms of an AP is given by S n, = 3n 2 - 4n. Determine the AP and the 12 th term. arithmetic progression WebFind the A.P. whose sum to n terms is 2n 2 +n A The required A.P. is 2,6,10,14,... B The required A.P. is 3,7,11,15,... C The required A.P. is 4,8,12,16,... D The required A.P. is 5,10,15,20,... Medium Solution Verified by Toppr Correct option is B) Given, S n=2n 2+n Now, a 1=S 1=2(1) 2+1=3 a 2=S 2−S 1=2(2) 2+2−3=7 technics sa 303 review
If Sn = 2n^2 + 3n. Find 16th term of AP - Teachoo - CBSE Sample …
WebEnglish Medium Class 10 In an AP, if Sn = n (4n + 1), find the AP. - Mathematics Advertisement Remove all ads Advertisement Remove all ads Sum In an AP, if S n = n (4n … WebSolution: The sum of n terms S n = 441 Similarly, S n-1 = 356 a = 13 d= n For an AP, S n = (n/2) [2a+ (n-1)d] Putting n = n-1 in above equation, l is the last term. It is also denoted by a n. The result obtained is: S n -S n-1 = a n So, 441-356 = a n a n = 85 = 13+ (n-1)d Since d=n, n (n-1) = 72 ⇒n 2 – n – 72= 0 Solving by factorization method, WebIn an AP, if Sₙ = n (4n + 1), find the AP Solution: Given, the expression for the sum of the terms is Sₙ = n (4n + 1) We have to find the AP. Put n = 1, S₁ = 1 (4 (1) + 1) = 4 + 1 = 5 Put n … spath and kelly 2017